x^2+(x+4)^2=19^2

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Solution for x^2+(x+4)^2=19^2 equation: 



x^2+(x+4)^2=19^2

We move all terms to the left:

x^2+(x+4)^2-(19^2)=0

We add all the numbers together, and all the variables

x^2+(x+4)^2-361=0

We move all terms containing x to the left, all other terms to the right

x^2+(x+4)^2=361

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